Document paths

Many APIs in Elasticsearch describe a path to a document. In NEST, besides generating a constructor that takes an Index and Id separately, we also generate a constructor that allows you to describe the path to your document more succinctly using a an instance of the DocumentPath<T> type.

Creating new instances

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here we create a new document path based on Project with the id 1

IDocumentPath path = new DocumentPath<Project>(1);
Expect("project").WhenSerializing(path.Index);
Expect(1).WhenSerializing(path.Id);

You can still override the inferred index name

path = new DocumentPath<Project>(1).Index("project1");
Expect("project1").WhenSerializing(path.Index);

and there is also a static way to describe such paths

path = DocumentPath<Project>.Id(1);
Expect("project").WhenSerializing(path.Index);
Expect(1).WhenSerializing(path.Id);

Creating from a document type instance

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if you have an instance of your document you can use it as well generate document paths

var project = new Project { Name = "hello-world" };

here we create a new document path based on the instance of Project, project

IDocumentPath path = new DocumentPath<Project>(project);
Expect("project").WhenSerializing(path.Index);
Expect("hello-world").WhenSerializing(path.Id);

You can still override the inferred index name

path = new DocumentPath<Project>(project).Index("project1");
Expect("project1").WhenSerializing(path.Index);

and again, there is also a static way to describe such paths

path = DocumentPath<Project>.Id(project);
Expect("project").WhenSerializing(path.Index);

DocumentPath<Project> p = project;

An example with requests

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var project = new Project { Name = "hello-world" };

we can see an example of how DocumentPath helps your describe your requests more tersely

var request = new IndexRequest<Project>(2) { Document = project };
request = new IndexRequest<Project>(project);

when comparing with the full blown constructor and passing document manually, DocumentPath<T>'s benefits become apparent. Compare the following request that doesn’t use DocumentPath<T> with the former examples

request = new IndexRequest<Project>(IndexName.From<Project>(), 2)
{
    Document = project
};

Much more verbose, wouldn’t you agree?

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